pyvista.core._validation.check.check_shape#
- check_shape(arr, /, shape, *, name='Array')[source]#
Check if an array has the specified shape.
- Parameters:
- arrarray_like
Array to check.
- shape
int
,tuple
[int
, …] |list
[int
,tuple
[int
, …]],optional
A single shape or a list of any allowable shapes. If an integer,
i
, the shape is interpreted as(i,)
. Use a value of -1 for any dimension where its size is allowed to vary, e.g.(-1,3)
if any Nx3 array is allowed. Use()
for the shape of scalar values (i.e. 0-dimensional). If a list, the array must have at least one of the specified shapes.- name
str
, default: “Array” Variable name to use in the error messages if any are raised.
- Raises:
ValueError
If the array does not have any of the specified shape(s).
See also
Examples
Check if an array is one-dimensional.
>>> import numpy as np >>> from pyvista import _validation >>> _validation.check_shape([1, 2, 3], shape=(-1))
Check if an array is one-dimensional or a scalar.
>>> _validation.check_shape(1, shape=[(), (-1)])
Check if an array is 3x3 or 4x4.
>>> _validation.check_shape(np.eye(3), shape=[(3, 3), (4, 4)])